(9/x+1)^2-2(9/x+1)=3

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Solution for (9/x+1)^2-2(9/x+1)=3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(9/x+1)^2-(2*(9/x+1)) = 3 // - 3

(9/x+1)^2-(2*(9/x+1))-3 = 0

(9/x+1)^2-2*(9/x+1)-3 = 0

(9*x^-1+1)^2-2*(9*x^-1+1)-3 = 0

(9*x^-1+1)^2-2*(9*x^-1+1)-3 = 0

81*x^-2-3-1 = 0

81*x^-2-4 = 0

81*x^-2-4 = 0

81*x^-2 = 4 // : 81

x^-2 = 4/81

-2 < 0

1/(x^2) = 4/81 // * x^2

1 = 4/81*x^2 // : 4/81

81/4 = x^2

x^2 = 81/4 // ^ 1/2

abs(x) = 9/2

x = 9/2 or x = -9/2

x in { 9/2, -9/2 }

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